Monday, 24 October 2016

Amcat Previous Years Automata and Computer Programming Questions

Amcat Previous Years Automata and Computer Programming Questions

1)There is a  colony of 8 cells arranged in a straight line where each day every cell competes with its adjacent cells(neighbour).
Each day, for each cell, if its neighbours are both active or both inactive, the cell becomes inactive the next day,. otherwise itbecomes active the next day.
Assumptions:
The two cells on the ends have single adjacent cell, so the other adjacent cell can be assumsed to be always inactive.
Even after updating the cell state. consider its pervious state for updating the state of other cells. Update the cell informationof allcells simultaneously.
Write a fuction cellCompete which takes takes one 8 element array of integers cells representing the current state of 8 cells and one integer days representing te number of days to simulate.
An integer value of 1 represents an active cell and value of 0 represents an inactive cell.
program:
int* cellCompete(int* cells,int days)
{
//write your code here
//function signature ends
TESTCASES 1:
INPUT:
[1,0,0,0,0,1,0,0],1
EXPECTED RETURN VALUE:
[0,1,0,0,1,0,1,0]
TESTCASE 2:
INPUT:
[1,1,1,0,1,1,1,1,],2
EXPECTED RETURN VALUE:
[0,0,0,0,0,1,1,0]
2) The Least-Recently-Used(LRU) cache algorithm exists the element from the cache(when it's full) that was least-recently-used. After an element is requested from the cache, it should be added to the cache(if not already there) and considered the most-recently-used element in the cache.
Given the maximum size of the cache and a list of integers(to request from the cache), calculate the number of cache misses using the LRU cache algorithm. A cache miss occur when the requested integer does not exist in the cache.
Initially, the cache is empty.
The input to the function LruCountMiss shall consist of an integer max_cache_size,  an array pages and its length len.
The function should return an integer for the number of cache misses using the LRU cache algorithm.
Assume that the array pages always has pages numbered from 1 to 50.
TESTCASES:
TESTCASE1:
INPUT:
3,[7,0,1,2,0,3,0,4,2,3,0,3,2,1,2,0],16
EXPECTED RETURN VALUE:
11
TESTCASE 2:
INPUT:
2,[2,3,1,3,2,1,4,3,2],9
EXPECTED RETURN VALUE:
8
EXPLANATION:
The following page numbers are missed one after the other 2,3,1,2,1,4,3,2.This results in 8 page misses.
CODE:
int lruCountMiss(int max_cache_size, int *pages,int len)
{
//write tour code
}
3) Write a function to insert an integer into a circular linked _list whose elements are sorted in ascending order 9smallest to largest).
The input to the function insertSortedList is a pointer start to some node in the circular list and an integer n between 0 and 100. Return a pointer to the newly inserted node.
The structure to follow for a node of the circular linked list is_
Struct CNode ;
Typedef struct CNode cnode;
Struct CNode
{
Int  value;
Cnode* next;
};
Cnode* insertSortedList (cnode* start,int n
{
//WRITE YOUR CODE HERE
}
//FUNCTION SIGNATURE ENDS
TestCase 1:
Input:
[3->4->6->1->2->^],5
Expected Return Value:
[5->6->1->2->3->4->^]
TestCase  2:
Input:
[1->2->3->4->5->^],0
Expected Return Value:
[0->1->2->3->4->5->^]
4) A system that can run multiple concurrent jobs on a single CPU have a process of choosing which task hast to run when, and how to break them up, called “scheduling”. The Round-Robin policy for scheduling runs each job for a fixed amount of time before switching to the next job. The waiting time fora job is the total time that it spends waiting to be run. Each job arrives at particular time for scheduling and certain time to run, when a new job arrives, It is scheduled after existing jobs already waiting for CPU time
Given list of job submission, calculate the average waiting time for all jobs using Round-Robin policy.
The input to the function waitingTimeRobin consist of two integer arrays containing job arrival and run times, an integer n representing number of jobs and am integer q  representing the fixed amount of time used by Round-Robin policy. The list of job arrival time and run time sorted in ascending order by arrival time. For jobs arriving at same time, process them in the order they are found in the arrival array. You can assume that jobs arrive in such a way that CPU is never idle.
The function should return floating point value for the average waiting time which is calculated using round robin policy.
Assume 0<=jobs arrival time < 100 and 0<job run time <100.
5) Problem:
Mooshak the mouse has been placed in a maze.There is a huge chunk of cheese somewhere in the  maze.
The maze is represented as a two-dimentional array of integers, where 0 represents  walls.1 repersents paths where mooshak can move and 9 represents the huge chunk of cheese. Mooshak starts in the top-left corner at 0.0
Write a method isPath of class MazePath to determine if Mooshak can reach the huge chunk of cheese. The input to isPath  consists of a two- dimentional array gnd for the maze matrix. the method  should return 1 if there is a path from Mooshak to the cheese.and 0 if not Mooshak is not allowed to leave the maze or climb on walls.
EX:8 by 8(8*8)  matrix maze where Mooshak can get the cheese.
1 0 1 1 1 0 0 1
1 0 0 0 1 1 1 1
1 0 0 0 0 0 0 0
1 0 1 0 9 0 1 1
1 1 1 0 1 0 0 1
1 0 1 0 1 1 0 1
1 0 0 0 0 1 0 1
1 1 1 1 1 1 1 1
Test Cases:
Case 1:
Input:[[1,1,1,][9,1,1],[0,1,0]]
Expected return value :1
Explanation:
The piece of cheese is placed at(1,0) on the grid Mooshak can move from (0,0) to (1,0) to reach it or can move from (0,0) to (0,1) to (1,1) to (1,0)
Test case 2:
Input:
[[0,0,0],[9,1,1],[0,1,1]]
Expected return value:0
Explanation:
Mooshak cannot move anywhere as there exists a wall right on (0,0)
Code:
(C Language)
//include header files needed by your program
// some libray functionality may be restricted
// define any function needed
// fucion signature begins, this function is required
Int isPath(int **grid,int m,int n)
{
// write your code here
}
//function signature ends
Java Code:
//import librays packages needed by your program
// some clases with in a package may be restricted
//define any class and method needed
//class begins ,this class is required
Public class MazePath
{
 Public static int isPath(int[][] grid)
// insert your code here
}
// method signature ends
}

Program :

Int isPath(int **grid,int m,int n)
{
      Return SolveMazeUtil(grid,0,0,m,n);
}
Int SolveMazeUtil(int **grid,x,y,m,n)
{
                If(x>=0 && x < m && y>=0 && y<n)
                {                 
                                 if(grid[x][y]==9))
                                {
                                                return 1;
                                }
                                // Check if maze[x][y] is valid
                                if(grid[x][y] == 1)
                                {
                                                /* Move forward in x direction */
                                                if (solveMazeUtil(grid, x+1, y, m,n) == 1)
                                                                return 1;                                             
                                                /* If moving in x direction doesn't give solution then
                                                                Move down in y direction  */
                                                if (solveMazeUtil(grid, x, y+1, m,n) == 1)
                                                                return 1; 
                                                /* If none of the above movements work then BACKTRACK:
                                                                unmark x,y as part of solution path */
                                                                return 0;
                                }    
                                return 0;
                }
                return 0;

}


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