**Asked in Elitmus**

# Elitmus previous questions

1. How many five digit numbers can be formed by using the digits 0,1,2,3,4,5 such that the number is divisible by 4?

2. Data sufficiency question:

There are six people. Each cast one vote in favour of other five. Who won the elections?

i) 4 older cast their vote in favour of the oldest candidate

ii) 2 younger cast their vote to the second oldest

3.

4. Decipher the following multiplication table: (See and learn how to solve cryptographical elitmus problem here:)

M A D

B E

-------------

M A D

R A E

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A M I D

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Explanation:

If a number has to be divisible by 4, the last two digit of that number should be divisible by 4.

So _ _ _ x y. Here xy should be a multiple of 4.

There are two cases:

Case 1: xy can be 04, 20 or 40

In this case the remaining 3 places can be filled in 4×3×2 = 24. So total 24×3 = 72 ways.

Case 2: xy can be 12, 24, 32, 52.

In this case, left most place cannot be 0. So left most place can be filled in 3 ways. Number of ways are 3×3×2 = 18. Total ways = 18×4 = 72.

Total ways = 144

There are six people. Each cast one vote in favour of other five. Who won the elections?

i) 4 older cast their vote in favour of the oldest candidate

ii) 2 younger cast their vote to the second oldest

Explanation:

Total possible votes are 6. Of which 4 votes went to the oldest person. So he must have won the election. Statement 1 is sufficient.

(Image taken while taking eLitmus Test, as you see eLitmus Test has New Layout from 2016)

M A D

B E

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M A D

R A E

-------------

A M I D

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Explanation:

It is clear that E = 1 as MAD×E=MAD

From the hundred's line, M + A = 10 + M or 1 + M + A = 10 + M

As A = 10 not possible, A = 9

So I = 0.

and From the thousand's line R + 1 = A. So R = 8.

M 9 D

B 1

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M 9 D

8 9 1

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9 M 0 D

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As B×D = 1, B and D takes 3, 7 in some order.

If B = 7 and D = 3, then M93×7 = _51 is not satisfying. So B = 3 and D = 7.

2 9 7

3 1

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2 9 7

8 9 1

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9 2 0 7

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5. If
is whole number, then how many numbers possible for N between 100 to 100?

Explanation:

= = =

Now this value should be whole number.

Let = w

As N is a positive integer, So for w = 0, 3, 6 we get N = 1, 9, 81.

Three values are possible.

Op 1: 15

Op 2: 10

Op 3: 21

Op 4: None of these

Op 5:

Correct Op : 4

7. If a

^{4}+(1/a

^{4})=119 then a power 3-(1/a

^{3}) =

a. 32

b. 39

c. Data insufficient

d. 36

Explanation:

Given that , adding 2 on both sides, we get :

Again, by subtracting 2 on both sides, we have,

Now, = = 12×3 = 36

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