1. How many five digit numbers can be formed by using the digits 0,1,2,3,4,5 such that the number is divisible by 4?
If a number has to be divisible by 4, the last two digit of that number should be divisible by 4.
So _ _ _ x y. Here xy should be a multiple of 4.
There are two cases:
Case 1: xy can be 04, 20 or 40
In this case the remaining 3 places can be filled in 4×3×2 = 24. So total 24×3 = 72 ways.
Case 2: xy can be 12, 24, 32, 52.
In this case, left most place cannot be 0. So left most place can be filled in 3 ways. Number of ways are 3×3×2 = 18. Total ways = 18×4 = 72.
Total ways = 144
2. Data sufficiency question: There are six people. Each cast one vote in favour of other five. Who won the elections? i) 4 older cast their vote in favour of the oldest candidate ii) 2 younger cast their vote to the second oldest
Total possible votes are 6. Of which 4 votes went to the oldest person. So he must have won the election. Statement 1 is sufficient.
(Image taken while taking eLitmus Test, as you see eLitmus Test has New Layout from 2016)