Saturday, 17 September 2016

Previous Years e-litmus Paper latest set 2

Asked in Elitmus


Elitmus previous questions


1. How many five digit numbers can be formed by using the digits 0,1,2,3,4,5 such that the number is divisible by 4?
Explanation:
If a number has to be divisible by 4, the last two digit of that number should be divisible by 4.
So _ _ _ x y.  Here xy should be a multiple of 4.
There are two cases:
Case 1: xy can be 04, 20 or 40
In this case the remaining 3 places can be filled in 4×3×2 = 24.  So total 24×3 = 72 ways.
Case 2: xy can be 12, 24, 32, 52.
In this case, left most place cannot be 0.  So left most place can be filled in 3 ways.  Number of ways are 3×3×2 = 18.  Total ways = 18×4 = 72.
Total ways = 144

2. Data sufficiency question:
There are six people. Each cast one vote in favour of other five. Who won the elections?
i)  4 older cast their vote in favour of the oldest candidate
ii) 2 younger cast their vote to the second oldest
Explanation:
Total possible votes are 6.  Of which 4 votes went to the oldest person.  So he must have won the election. Statement 1 is sufficient.

3.
(Image taken while taking eLitmus Test, as you see eLitmus Test has New Layout from 2016)

4. Decipher the following multiplication table: (See and learn how to solve cryptographical elitmus problem here:)
     M A D
          B E
-------------
     M A D
  R A E
-------------
  A M I D
-------------
Explanation:
It is clear that E = 1 as MAD×E=MAD
From the hundred's line, M + A = 10 + M or 1 + M + A = 10 + M
As A = 10 not possible, A = 9
So I = 0.
and From the thousand's line R + 1 = A. So R = 8.
     M 9 D
         B 1
-------------
     M 9 D
  8 9  1
-------------
  9 M 0 D
-------------
As B×D = 1, B and D takes 3, 7 in some order.
If B = 7 and D = 3, then M93×7 =   _51 is not satisfying. So B = 3 and D = 7.
     2 9 7
        3 1
-------------
     2 9 7
8  9  1
-------------
9 2 0 7
-------------
5. If 
log3N+log9N is whole number, then how many numbers possible for N between 100 to 100?
Explanation:
log3N+log9N = log3N+log32N = log3N+12log3N =32log3N
Now this value should be whole number.
Let 32log3N = w
log3N=23w
N=3(23w)
As N is a positive integer, So for w = 0, 3, 6 we get N = 1, 9, 81.
Three values are possible.

Ques. What will be obtained if 8 is subtracted from the HCF of 168, 189, and 231?
Op 1: 15
Op 2: 10
Op 3: 21
Op 4: None of these
Op 5:

Correct Op : 4

7. If a4 +(1/a4)=119 then a power 3-(1/a3) = 
a. 32 
b. 39
c.  Data insufficient
d.  36
Explanation:
Given that a4+1a4=119 , adding 2 on both sides, we get : (a2+1a2)2=121
a2+1a2=11
Again, by subtracting 2 on both sides, we have, (a1a)2=9
a1a=3
Now, a31a3 = (a1a)(a2+1a2+1) = 12×3 = 36





No comments:

Post a Comment